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8x+8=-2x^2
We move all terms to the left:
8x+8-(-2x^2)=0
We get rid of parentheses
2x^2+8x+8=0
a = 2; b = 8; c = +8;
Δ = b2-4ac
Δ = 82-4·2·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-8}{4}=-2$
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